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思路：单调递减栈，找「上一个比当前价格大的元素索引」。正序遍历，弹出所有 ≤ 当前价格的索引；跨度 = 当前索引 - 栈顶索引（栈空则为 当前索引 + 1）。
，更多细节参见搜狗输入法2026
[단독]폴란드, 韓 해군 최초 잠수함 ‘장보고함’ 무상 양도 안받기로，推荐阅读Line官方版本下载获取更多信息
"That will need to be paid off at some point," says Quilter Cheviot's Ben Barringer. "Having more debt means you've got more burden, and that means you've got less to spend on content."，详情可参考服务器推荐